Question

Cluster Question 2 A cup contains 195 g of coffee at 98.0°C. Suppose 61.3 g of 0°C ice is added to the coffee. Question 24 3 pt How much heat energy is needed to melt the ice cube? 834 kJ 256 kJ 138 kJ O 20.4 kJ Question 25 4 pts What is the temperature of the coffee after all of the ice melts? 103 degrees C O 55.5 degrees C W P X tv MacBook Pro

Answer 1

Soluo at Tc=98°C Here we have given, mass of coffee me = 195g Fee mi= 6113g mass of at Te =0°6 Ory Heat is needed to melt the ree will be Rice = 61.3(g)x X Imole ice 6.OKI 18.0152 gice 1 mole ile Herc, 18:01 120-1 me soption D corect = 20.4 KI] (free mass] 025 Here vice +96=> So that 2004 kJ re= m(AT) a 20.4 X10 X. 103 HT - If me T 98- 2004 8 103 = 72.97°C 195 x 4.18 Now, t Temperature of coffee atter all the ice melte will be f = miti Caf Metice 0 +19572:97x448 Mecit mele 195x448 s option B correct 26 The amount of energy coffee loose will be given as, 61,3 f 19 If 55.5063 aro - Me Co AT -:195) x 4.18% ( 98-55-3) 103 Leo qo =:34. 7 kg] - option D Am