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Hello! I mainly need part B fully answered but if you are willing to answer the rest that would be awesome! Thank you in advance

iPad? 10:50 PM 12%I My Notes Ask Your Let x be the number of different research programs, and let y be the mean number of patents per program. As in any business, a company can spread itself too thin. For example, too many research programs might lead to decline in overall research productivity. The following data are for a collection of pharmaceutical companies and their research programs Complete parts (a) through (e), given Zr . 90. ?? . 8. Zr2-1420-Xy2 11.5, ??? . 113, and ra-0.917. a) Draw a scatter diagram displaying the data. Submission Data (b) Verify the given sums Ex, Ey, E2, Ey2, Exy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places) (c) Find x, and y. Then find the equation of the least-squares line y-a+bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places) (d) Graph the least-squares line. Be sure to plot the point (x, y) as a point on the line.
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Answer #1

(a)

Following table shows the calculations:

X Y X^2 Y^2 XY
10 1.6 100 2.56 16
12 1.8 144 3.24 21.6
14 1.5 196 2.25 21
16 1.4 256 1.96 22.4
18 1 324 1 18
20 0.7 400 0.49 14
Total 90 8 1420 11.5 113

Sample size: n=6

Now,

S_{yy}=\sum y^{2}-\frac{\left (\sum y \right )^{2}}{n}=0.8333

S_{xx}=\sum x^{2}-\frac{\left (\sum x \right )^{2}}{n}=70

S_{xy}=\sum xy-\frac{\left (\sum x \right )\left (\sum y \right )}{n}=-7

The coeffcient of correlation is :

r=\frac{S_{xy}}{\sqrt{S_{xx}S_{yy}}}=\frac{-7}{\sqrt{0.8333\cdot 70}}=-0.917

(c)

\bar{x}=\frac{\sum x}{n}=15
\bar{y}=\frac{\sum y}{n}=1.3333

Slope of the regression equation is

b_{1}=\frac{S_{xy}}{S_{xx}}=-0.1

and intercept of the equation will be

b_{0}=\frac{1}{n}(\sum y - b_{1} \sum x)=2.833

So the regression equation will be

y'=2.833-0.1x

(d)

For graph first option is correct.

(e)

r^{2}=(-0.917)\cdot (-0.917)=0.84

explained: 84%

unexplained: 100% -84% = 16%

(f)

The predicted value is:

y'=2.833-0.1*18 = 1.033

Answer:1.03

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