Question

table 2.73 calculate the mean median standard deviation the first quartile the third quartile and the Iqr round to one decimal place

95. 75% of all years have an FTES: a. at or below: b. at or above: 96. The population standard deviation = 97. What percent of the FTES were from 528.5 to 1447.5? How do you know? 98. What is the IQR? What does the IQR represent? 99. How many standard deviations away from the mean is the median? Additional Information: The population FTES for 2005-2006 through 2010-2011 was given in an updated report. The da are reported here. Year 2005–06 2006-07 2007–08 2008-09 2009-10 2010-11 Total FTES 1,5851,690 1,735 1,935 2,021 (1,890 Table 2.73 100. Calculate the mean, median, standard deviation, the first quartile, the third quartile and the IQR. Round to one decim place. 101. What additional information is needed to construct a box plot for the FTES for 2005-2006 through 2010-2011 and box plot for the FTES for 1976-1977 through 2004-2005? 102. Compare the IQR for the FTES for 1976-77 through 2004-2005 with the IQR for the FTES for 2005-2006 throug 2010-2011. Why do you suppose the IQRs are so different? 103. Three students were applying to the same graduate school. They came from schools with different grading system Which student had the best GPA when compared to other students at his school? Explain how you determined your answe School Average GPA 2.7 3.2 Student GPA Thuy 2.7 Vichet 87 Kamala 8.6 Table 2.74 School Standard Deviation 0.8 20 h 0.4 75 8

Answer 1

The data is given as follows: Year Total FTES 2005-06 1,585 2006-07 1,690 2007-08 1,735 2008-09 1,935 2009-10 2,021 2010-11 1,890 The mean of the data is given as follow: =-3x n 1-1 1585 +1690+1735 +1935+2021+1890 10856 = 1809.33 Hence, the mean of the data is # = 1809.33. The median of the data is calculated as follows: Arrange the data in the increasing order as follows: [ 1585 | 1690 | 1735 I 1890 | 1935 | 2021

The median is given below: Medion 3 position +4h position) 2 1735+1890 2 3625 2 = 1812.5 Hence, the median of the data is 1812.5. The standard deviation of the data is calculated as follows: 1 $(x,-5) Vn-1 1=1 1585 – 1809.33)? +(1690-1809.33) +...+(1935–1809.33)’ +(2021 – 1809.33)? 6-1 1137193.333 = 165.6 Hence, the standard deviation of the data is s = 165.6.

The first and third quartile of the data are calculated as follows: The first quartile is the middle value of the lower half of the data. The third quartile is the middle value of the upper half of the data. 1585 | 1690 1735 1890 | 1935 | 2021 Lower half Upper half Hence, the first quartile is Q. = 1690 Hence, the third quartile is Q; = 1935 . The interquartile range of the data is calculated as follows: IQR = Q3 - Q. = 1935–1690 = 245 Hence, the interquartile range of the data is IQR = 245.