19. Given that is a standard normal random variable, what is the value of z if...
19. Given that z is a standard normal random variable, what is the probability that z ≥ -2.12? Select one: a. 0.4830 b. 0.9830 c. 0.017 d. 0.966
Given that z is a standard normal random variable, find z for each situation (to 2 decimals) a. The area to the right of z is 0.03. b. The area to the right of z is 0.045 c. The area to the right of z is 0.05 d. The area to the right of z is 0.1
Given that z is a standard normal random variable, find z for each situation (to 2 decimals) a. The area to the left of z is 0.2119 b. The area between -z and z is 0.903. c. The area between -z and z is 0.2052 d. The area to the left of z is 0.9951 e. The area to the right of z is 0.695
eBook Video Given that z is a standard normal random variable, find z for each situation (to 2 decimals). a. The area to the left of z is 0.209. (Enter negative value as negative number.) -0.81 b. The area between – z and z is 0.905. 1.1553 c. The area between – z and z is 0.2128 . d. The area to the left of z is 0.9951 . -2.58 e. The area to the right of z is 0.6915....
Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.) (a) The area to the right of z is 0.01 (b) The area to the right of z is 0.025. (c) The area to the right of z is 0.05(d) The area to the right of z is 0.10
3)using excel and Given that z is a standard normal random variable, what is the value for z0 if: a. P(z > z0) = 0.12 b. P(z < z0) = 0.2 c. P(z > z0) = 0.25 d. P(z < z0) = 0.3
eBook Video Given that z is a standard normal random variable, find z for each situation (to 2 decimals). Enter negative values as negative numbers. a. The area to the left of z is 0.2119. 1.66 b. The area between – 2 and z is 0.9030. 1.66 c. The area between – z and z is 0.2052 . 1 .26 d. The area to the left of z is 0.9948 . e. The area to the right of z is...
Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals). a. The area to the left of z is 0.8 b. The area to the left of z is 0.981 c. The area to the right of z is 0.6045 d. The area between -z and z is 0.82 (Hint: Enter the positive z-value)
Given that z is a standard normal random variable, find the z-score for a situation where the area to the right of z is 0.0901
4) Given that z is a standard normal random variable, find z for each situation The area to the left of z is .9750. The area between 0 and z is .4750. The area to the left of z is .7291. The area to the right of z is .1314. The area to the left of z is .6700. The area to the right of z is .3300.