Question

The 80-mm-radius wheel shown rolls to the left with a velocity of 850 mm/s. Knowing that the distance AD is 52 mm, determine the velocity of the collar and the angular velocity of rod AB when B=0 SO mm 250 mm 160 mm

Answer 1

(o) B-0. Wheel AD. "=0, - 45 in 100-900 - 11.25 tads) CAE (CD)-(DA)=80-50 - 30 mm -(C) -(30X1125) = 337.5 mm Rod AB - 15--1-(337.5 --- *[w. Vel , -338 mily's - 0

(6) B=90° Wheel AD. Ve=0. , 11.25 rad's tan y-Day =32,005 CADC = 94.34 mm -(CA),p=194.34)(11.25)=1061.3 mm/s -(1061.3 mm/s 32.005*1 Rod AB 80 sin p=18.663° Plane motion Translation with A+ Rotation about A.

---- - Draw velocity vector diagram. $ = 180*-7-1909+) =90°-32.0050 - 18.663* - 39.332 Law of sines (10613)sin 39.332 sin 108.663 710 mms sind sin (90 + ) = 710 mm/s v siny Von sin (90° +) = 593.8 mm's (1061.3) sin 32.005 sin 108.663 = 2.37 rady )