Calculate the number of moles os sodium hydroxide (NaOH) present in 42.0 mL of a 0.629...
A student mixes 67.0 mL of a 2.01 M sodium hydroxide solution with 22.8 mL of 6.45 M hydrochloric acid. The temperature of the mixture rises 20.8°C. The density of the resulting solution is 1.00 g and mL has a specific heat capacity of 4.184 The heat capacity of the calorimeter is 16.97 g.°c °C Part 1: (a) Identify the limiting reagent for the reaction. NaOH Part 2 out of 3 (b) Calculate the heat of reaction (in J). Arxn...
A student mixes 67.0 mL of a 2.01 M sodium hydroxide solution with 22.8 mL of 6.45 M hydrochloric acid. The temperature of the mixture rises 20.8°C. The density of the resulting solution is 1.00 and mL has a specific heat capacity of 4.184 The heat capacity of the calorimeter is 16.97 °C J J 8°C Part 1: (a) Identify the limiting reagent for the reaction. NaOH Part 2 out of 3 (b) Calculate the heat of reaction (in J)....
A student mixes 67.0 mL of a 2.01 M sodium hydroxide solution with 22.6 mL of 6.45 M hydrochloric g acid. The temperature of the mixture rises 19.0°C. The density of the resulting solution is 1.00 and mL J has a specific heat capacity of 4.184 The heat capacity of the calorimeter is 16.97 g.°C J Part 1: (a) Identify the limiting reagent for the reaction. NaOH V Part 2 out of 3 (b) Calculate the heat of reaction (in...
Calculate the moles and mass of solute in 250.0 ml of 6.00 m sodium hydroxide. Calculate the volume of 6.00 m sodium hydroxide that would required to obtain 60.0 grams of sodium hydroxide.
A chemist titrates 150.0 mL of a 0.4938 M sodium hydroxide (NaOH) solution with 0.6911 M HNO, solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO2 solution added. pH = 0
A student mixes 35.2 mL of a 3.11 M sodium hydroxide solution with 35.3 mL of 2.95 M hydrochloric acid. The temperature of the mixture rises 21.7C.The density of the resulting solution is 1.00 g/ml and has a specific heat capacity of 4.184 The heat capacity of the calorimeter is 3.86. Calculate the heat of reaction (in J). (answer in scientific notation)
A student mixes 67.0 mL of a 2.01 M sodium hydroxide solution with 22.8 mL of 6.45 M hydrochloric acid. The temperature of the mixture rises 20.8°C. The density of the resulting solution is 1.00 g and mL J has a specific heat capacity of 4.184 g.°C The heat capacity of the calorimeter is 16.97 °C Part 1: (a) Identify the limiting reagent for the reaction. NaOH Part 2: a X (b) Calculate the heat of reaction (in J). Arxn--8.17...
How many moles of NaOH are present in 14.5 mL of 0.220 M NaOH? moles: How many grams of solute are present in 355 mL of 0.670 M KBr? mass of solute: A 37.0 mL aliquot of a 0.600 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water should be added? volume of water: How many grams of chlorine gas are needed to make 5.30 x 10g of a solution that is...
1. Determine the number of moles of reagent in the following solutions: a. 25.00 mL of 0.10 M acetic acid b. 5.55 mL of 0.092 M NaOH C. 0.50 mL of 0.087 M HCI 2. A buffer solution contains 0.120 M acetic acid and 0.150 M sodium acetate. a. How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution? b. If we add 5.55 mL of 0.092 M NaOH to the solution in...
4. Calculate the volume of 1 M sodium hydroxide (NaOH) needed to prepare 10 ml of a 0.10 M sodium hydroxide solution. 5. Calculate the volume of 1 M hydrochloric acid (HCI) needed to prepare 10 mL of a 0.10 M hydrochloric acid solution. 6. Determine the volumes of 0.10 M CH3COOH and 0.10 M CH3COONa required to prepare 10 ml of the following pH buffers. (Note: the pka of CH3COOH =4.7) C. pH 3.7 b. pH 47 C. pH...