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Here are summary statistics for randomly selected weights of newborn girls: n = 163, x = 28.6 hg, S=6.9 hg. Construct a confi
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Answer #1

SOLUTION:

From given data,

Here are summary statistics for randomly selected weights of newborn​ girls: n=163​, \bar{x} =28.6 hg, s = 6.9 hg. Construct a confidence interval estimate of the mean.

Use a 95​% confidence level. Are these results very different from the confidence interval 27.6 hg < \mu < 30.0 hg with only 20 sample values, \bar{x} = 28.8 hg, and s = 2.5 ​hg?

n = Sample Size = 163

\bar{x} =Sample Mean = 28.6 hg

s = Sample standard deviation = 6.9 hg

What is the confidence interval for the population mean \mu ?

SE = s / sqrt(n)

SE = 6.9 / sqrt(163) =0.540449

Take

95% confidence interval

95/100 = 0.95

Significance level = \alpha = 1-0.95 = 0.05

\alpha/2 = 0.05/2 = 0.025

Degree of freedom = df = n - 1 = 163 - 1 = 162

From Table,

critical values of t

t\alpha/2,df = t0.025,162 = 1.9747

Confidence Interval:

\bar{x}\pm t\alpha/2,df * SE

28.6 \pm (1.9747 * 0.540449)

28.6 \pm 1.0672246403

( 28.6 - 1.0672246403 , 28.6+1.0672246403)

(27.6 , 29.7)

27.6 hg <  \mu <  29.7 hg (Rounded to one decimal place.)

Are the results between the two confidence intervals very different?

We have the confidence interval 27.6 hg < \mu < 30.0 hg.

Answer : option (A)

No, because the confidence interval limits are similar.

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