For a crest vertical curve, with the following data, Station of BVC: 10+50 Station of Vertex:...
For a crest vertical curve, with the following data,
Station of BVC: 10+50
Station of Vertex: 18+00
Station of EVC: 20+50
Elevation of Vertex: 1000ft
Beginning Grade: +3.50%
Ending Grade: -3.50%
a) At what station is the highest point located?
b) What is the elevation of the high point?
c) An information center is located at station 18+50.98, what is the elevation of the information center?
d) What is the AASHTO K-value for the vertical curve?
Homework Answers
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For a crest vertical curve, with the following data,
Station of BVC: 10+50
Station of Vertex:...
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at...
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at station 40+00.00 at an elevation of 100.00 ft. The design speed is 70 mi/h. If the length is 1084 ft, determine: (b) The station of the BVC (3 pts (c) The elevation of the BVC (3 pts (d) The station of the EVC (3 pts) (e) The elevation of the EVC (3 pts) (1) The station of the highest point on the curve (4...
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Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
9:381 LTE Problem 1 A crest vertical curve is to be designed to join a +2% grade with a-2% at a s...
9:381 LTE Problem 1 A crest vertical curve is to be designed to join a +2% grade with a-2% at a section of a two-lane highway. Determine the minimum length of the curve if the design speed of the highway is 60 mph and SL. Assume that a-9.34 ftsec' and that the perception-reaction time is 2.5 sec. Problem2 A crest vertical curve is to be designed to join a +3% grade with a-2% grade at a section of a two-lane...
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45....
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45. The beginning of vertical curve (BVC) is at station 81+00. A-3.6% curve meets a +4.4% curve at the point of vertical intersection (PVI), which is at elevation 425.38 ft. What is the elevation of the point on the curve under the bridge? Problem 5 The grade into a vertical sag curve is -2%. The curve length is 1,400 ft. The grade out of the...
A vertical parabolic curve is to be used as a crest curve, and it is desired...
A vertical parabolic curve is to be used as a crest curve, and it is desired to know the location and elevation of the high point. The curve is 550 feet long and a grade of +3.6% intersects a grade of-4% at station 40+80.00. Calculate the high point of the curve if the intersection at station 40+80.00 is at elevation of 625 feet.
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and...
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT. Solve this problem using parabolic equation and offset method.
An equal-tangent crest vertical curve has a 50-mi/h design speed. The initial grade is +3%. The...
An equal-tangent crest vertical curve has a 50-mi/h design speed. The initial grade is +3%. The high point is at station 33 + 40.76 and the PVT is at station 37 + 24.66. What is the elevation difference between the high point and the PVT?
Q1. A +2 percent grade on an arterial highway intersects with a -1 percent grade at...
Q1. A +2 percent grade on an arterial highway intersects with a -1 percent grade at station (5+357.28) at an elevation of 90m. If the design speed of the highway is 100 Km/h, determine the stations and elevations of the BVC and EVC, the elevation of each 30-m station, and the higlh point Q2. Determine the minimum length of a vertical curve if the grades are +4% and-200. Design speed is 120 km/hr. State assumptions used in solving this problem....
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.-...
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.- 1 134.50, gi-30%, g2+ +1.4%, L :300, what is the station and elevation of the BVC? a) 17+00; 1138.00 17+00; 1139.44 h9+50; 1142.00 d) 19+50; 1138.00 7. Based on the following Vertical Curve information (units in ft.): PVI Sta 1 134.50, gi .-30%, g2+ +1.4%, L . 500, what is the elevation on the curve at Sta. 23 22+00, PVI Elev. a) 1138.49 b)...
2. A crest vertical curve is to be designed by joining a +4% initial tangent with...
2. A crest vertical curve is to be designed by joining a +4% initial tangent with a final -3% tangent. The station location and elevation of VPC are 250+45 and 500 ft respectively. The design speed is 50 mph on the curve. Using AASHTO geometric design guideline, determine: (a) Station location of VPT. (b) Vertical offset at each 1/4 of length distance from VPC.
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at station 40+00.00 at an elevation of 100.00 ft. The design speed is 70 mi/h. If the length is 1084 ft, determine: (b) The station of the BVC (3 pts (c) The elevation of the BVC (3 pts (d) The station of the EVC (3 pts) (e) The elevation of the EVC (3 pts) (1) The station of the highest point on the curve (4...
Problem #3 (20 Points) Vertical Curve Problem (Use both Tangents) See Attached Vertical Curve Drawing Station Tangent Elevation Tangent Offset В VC 45+00 45+50 46+00 PVI 678.14 46+18.47 46+50 47+00 47+50 EVC I. gl=+4.3%, g2 =-3.196, L = 300, 2. Calculate stations for BVC and EVC and insert into table 3. Calculate station for high/low point and insert into table (this will be located between stations already entered in table, and not yet highlighted). 4. Calculate ALL tangent elevations, tangent...
9:381 LTE Problem 1 A crest vertical curve is to be designed to join a +2% grade with a-2% at a section of a two-lane highway. Determine the minimum length of the curve if the design speed of the highway is 60 mph and SL. Assume that a-9.34 ftsec' and that the perception-reaction time is 2.5 sec. Problem2 A crest vertical curve is to be designed to join a +3% grade with a-2% grade at a section of a two-lane...
Problem 4 A 500 ft long sag vertical curve passes under a bridge at station 82+45. The beginning of vertical curve (BVC) is at station 81+00. A-3.6% curve meets a +4.4% curve at the point of vertical intersection (PVI), which is at elevation 425.38 ft. What is the elevation of the point on the curve under the bridge? Problem 5 The grade into a vertical sag curve is -2%. The curve length is 1,400 ft. The grade out of the...
A vertical parabolic curve is to be used as a crest curve, and it is desired to know the location and elevation of the high point. The curve is 550 feet long and a grade of +3.6% intersects a grade of-4% at station 40+80.00. Calculate the high point of the curve if the intersection at station 40+80.00 is at elevation of 625 feet.
Q1. A +2 percent grade on an arterial highway intersects with a -1 percent grade at station (5+357.28) at an elevation of 90m. If the design speed of the highway is 100 Km/h, determine the stations and elevations of the BVC and EVC, the elevation of each 30-m station, and the higlh point Q2. Determine the minimum length of a vertical curve if the grades are +4% and-200. Design speed is 120 km/hr. State assumptions used in solving this problem....
6. Based on the following Vertical Curve information (units in ft.): PVi Sta. 22+00, PVI Elev.- 1 134.50, gi-30%, g2+ +1.4%, L :300, what is the station and elevation of the BVC? a) 17+00; 1138.00 17+00; 1139.44 h9+50; 1142.00 d) 19+50; 1138.00 7. Based on the following Vertical Curve information (units in ft.): PVI Sta 1 134.50, gi .-30%, g2+ +1.4%, L . 500, what is the elevation on the curve at Sta. 23 22+00, PVI Elev. a) 1138.49 b)...
2. A crest vertical curve is to be designed by joining a +4% initial tangent with a final -3% tangent. The station location and elevation of VPC are 250+45 and 500 ft respectively. The design speed is 50 mph on the curve. Using AASHTO geometric design guideline, determine: (a) Station location of VPT. (b) Vertical offset at each 1/4 of length distance from VPC.
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