Question

(Approximate Method Gravity Frame) Problem 4. VERTICAL LOAD ON FRAME METHOD. Determine the approximate SUPPORT REACTIONS at "B". All supports are fixed. (10 points) Mg = 1.5 kn Bx = BY = 12 ft 4 kft 2 lnt 15 ft 40 ft B 25 ft

Answer 1

1.5k/ft Semn 12 ft I 4k/ ft I 2 klft I н E F T isht 464 2.5k 2.5ft 1 A 7777 -4oft 2567 while souwing such type of probleon some assumptions are made Assumptions : (0 connections are rigid: (2) Inflection points are at 10% of bearm spans foros rigid connection to Column No Ascial loads generated m beams. 3 Steps: calculating internal loadings at inflection points. (at inflection point moment is zero) FBD of ER: 2k/bt 中中中中 po K 32 ft ME=DA VE Meget He=0&H=0 alo horizontal wad 0 SME=0 = (2x32X16) + FX32) VES-2x32x16 32 VE -32k

FBD OF G H I 4kift quif Muco Haro H K 20ft-> @ EM TO VG x 20 - 4x20x10 VG= .4x20x10 20 = 40K @ FBI of II: 1.5k/h Tv 1 H20 A J K 20 ft → Đ E Mg=0= VIX 20 - (15X20X10) VIC 1.5x20x10 - Isk 20 1.5K/ft Now. FBD of BFG I odda tisk V = -32 [VG=40k 14 - 2Bx=0 (alo horizontal force) Ba { By = 0 By + (-32)-15-40-(4x2) * (2 •5 XG)-(1.5X2.5)=0 By - By 32 +55+ 8+10+ 3.75 By = 108.75k Now, Emy zo > 842+(40x2.5)+(1542-57-324 ) +(1.5*2.5 *»* + (2.5x4 )x 2.5-(4x2) x2 = 10.1875k-ft
i have included all steps and calculations. Also some assumptios are made to solve the problem.If you find this helpful then gives a thumbs up!

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