Question

Using High Assembly language Write a program to produce a number table as described here. This table should be built from a single integer value provided by the user. The program will display a square 5X5 of various numbers. The entered number should appear in an X like pattern across the table, diagonally across the table. Every other spot besides the X pattern should be filled with a number. Those excess numbers should start with one bigger than the entered number and increment by one for every additional excess number used.

For example, the following output should be produced when the user inputs the starting value 15:

Gimme a starting value: 15
15 16 17 18 15
19 15 20 15 21
22 23 15 24 25
26 15 27 15 28
15 29 30 31 15

Answer 1

Below C++(High Assembly Language) program will produce the required pattern.

Program starts;

#include<iostream>
#define GRID_SIZE 5
using namespace std;

int main(){

int x,current_value,i,j;
cout<<"gimme a number: ";
cin>>x;
cout<<endl;

//Upper half Grid
for(int i=0 ; i<GRID_SIZE/2 ; i++){
   current_value = x + i*(GRID_SIZE-2) + 1;
   for(j=0 ; j<i ; j++){
       cout<<current_value++<<" ";
   }  
   cout<<x<<" ";  
   for(j=i+1 ; j<GRID_SIZE-1-i ; j++){
       cout<<current_value++<<" ";
   }  
   cout<<x<<" ";  
   for(j=GRID_SIZE-i ; j<GRID_SIZE ; j++){
       cout<<current_value++<<" ";
   }  
   cout<<endl;
}

//Lower half Grid
for(int i=GRID_SIZE/2 ; i<GRID_SIZE ; i++){
   current_value = x + i*(GRID_SIZE-2) + 1;
   for(j=0 ; j<GRID_SIZE-i-1 ; j++){
       cout<<current_value++<<" ";
   }
   cout<<x<<" ";  
   for(j=GRID_SIZE-i ; j<i ; j++){
       cout<<current_value++<<" ";
   }
      
   if(GRID_SIZE%2==0 || i!=GRID_SIZE/2) {
   cout<<x<<" ";
}
  
   for(j=i+1 ; j<GRID_SIZE ; j++){
       cout<<current_value++<<" ";
   }
   cout<<endl;
}
   return 4;
}

Here is the Screenshot of output of the above program.

Here is the Screenshot of code.