Given that : there are six coins, among one is couterfeit weight than the rest
strategy:
divide six coins into 3 parts
2 coins, 2 coins, 2 coins
now :test any of two coins agains another two coins (remember that there are other two coins also which are not weighing)
//here counter feit coin may present in these four or may be not
lets see both the case
case1: //if present
then one of them will weigh more than other pair
so select that pair which is heavier
and test those two coins one against another, we will find the heavier one
case2: //if not present
then counterfeit coin must be present in other pair which is not weighing
so, take that pair
and test those two coins one against another, we will find the heavier one
//so in all cases
inorder to find counterfeit coin, in this strategy
we need 2 tries
//PLS give a thumbs up if you find this helpful, its helps alot, thanks
1.13 (Counterfeit Coin Problem) We are given six coins, one of which is counterfeit and is...
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