Question

What is the molar mass of an ideal gas if a 0.72 g sample of this gas occupies a volume of 475./. mat 50.0°C and 720. mm Hg? Flag question Select one: O a. 42.40 g/mol O b. 16.98 g/mol c. 660.69 g/mol O d. 1.51 g/mol Oe. 20.17 g/mol son 8 Consider the following reaction: 2Al(s) + 3Cl2(g) - 2AlCl3(s), AH = -1391 kJHow many moles of Al are required to releasee 714.3 kJ of energy (assume 100% yield) et red out of Select one: Ca. 1.03 mol question Ob. 1.95 mol OC 0.26 mol d. 0.51 mol e. 3.89 mol sion of 1 mol of an ideal monatomic gas from 11.6L to 54

Answer 1

PV n = ) 1st Question For an ideal gas, PV = nRT R=0.082 afmoll molok RT 720 mm Hg = 720 mm Hg = 0.947 afm P= Pressure = 760 mm .Hg V = volume 475.7 mL 0.4757 L T = Temperature = 50.0°C = 323 K PV Mole, n= 102475346 RT - = 11 (0.947 afm) x (0.4757L) 10.082 afraid X 323K 0.017o mol mol/wrotex) Molaro Mass = 1.72 g 0.017o mol 42.35 a/mol is 42.40 g/mol Answer: @ 42:40 ) mof

2nd Question Given Reaction: 2 A1 (9) + 3C12(3) - 2 A1 C13(5) Here, AH AH = -1391 KL, BE, lie, 2 mole of Al(s) is produced luced -1391 kJ energy. So, 714,3 Kg energy produced from 74.3kx8) : :. Answer: @. 1.05 mol 714.3 kJ x 2 mol 1391 kJ = 1.027 mol ~ 1.03 mot