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The top and bottom surfaces of a metal block each have an area of A =...

The top and bottom surfaces of a metal block each have an area of A = 0.025 m2, and the height of the block is d = 0.12 m. At the top surface of the block, a force F1 is applied to the right, while at the bottom surface of the block, a force F2 is applied to the left, causing a shear in the metal block. If F1 = F2 = 41 ✕ 106 N and the displacement between the two edges due to the shear is 1.21  10-3 m, what is the shear modulus of the metal (in N/m2)?

N/m2

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Answer #1

А → F 10 here, fi = F 418100 N F 2 f 2 = -3 1.21Xio l d x 0. 12 ya 0.025 2 therefore, Shear Modulus , n AS Ed V An alx106x0.1

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