Answer:
A).
XEY ; DD = Pure breeding white male
XeXe; dd = Pure breeding brown female
b).
XEY; DD (male) x (female) XeXe; dd ------Parents
Xe d |
|
XE D |
XEXe ; Dd (white female) |
Y D |
XeY; Dd (black male) |
All daughters are white color and all sons are with black color
Expected phenotypic ratio = 1:1
c).
XEXe; Dd (female) x XeY; Dd (male)—F1xF1
XeD |
Xed |
YD |
Yd |
|
XED |
XEXe; DD (white) |
XEXe; Dd (white) |
XEY; DD (white) |
XEY; Dd (white) |
XEd |
XEXe; Dd (white) |
XEXe; dd (white) |
XEY; Dd (white) |
XEY; dd (white) |
XeD |
XeXe; DD (black) |
XeXe; Dd (black) |
XeY; DD (black) |
XeY; Dd (black) |
Xed |
XeXe; Dd (black) |
XeXe; dd (brown) |
XeY; Dd (black) |
XeY; dd (brown) |
Female |
Male |
Phenotypic ratio = Black : White : Brown = 6:8:2 = 3:4:1
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As it is
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#1.
In peas, flower location and
plant height are controlled by genes that follow Mendel’a law. One
allele at each locus is donminat to the other at that locus: (i)
AXIAL FLOWERS (A), terminal flowers (a), and (ii) TALL PLANT (T),
short plant (t). A pure breeding plant for the dominant traits is
mated with pure breeding plant for the recessive traits. What
possible gametes can F1 individuals that interbreed make?
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