8 Hour shift | ![]() |
![]() |
|
3 | -2 | 4 | |
6 | 1 | 1 | |
8 | 3 | 9 | |
4 | -1 | 1 | |
5 | 0 | 0 | |
8 | 3 | 9 | |
2 | -3 | 9 | |
4 | -1 | 1 | |
6 | 1 | 1 | |
4 | -1 | 1 | |
Total | 50 | 0 | 36 |
Sum = Sum of error = 50
= 0
= 36
Standard Deviation =
=
= 1.8974
S =
=
= 2.0000
Mean
=
Median = Middle most value that are arrange in ascending order = 5th & 6th value
taking the average of it = ( 4 + 5 ) / 2 = 4.5
Median = 4.5
Mode = is the value occure most frequently = 4 ( 4 occurs 3 times in the data)
Minimum score = 2
Maximum score = 8
Range = Maximum - Minimum = 8 - 2 = 6
For 12 Hour Shift
12 hour shift | ![]() |
![]() |
|
5 | -1 | 1 | |
8 | 2 | 4 | |
5 | -1 | 1 | |
5 | -1 | 1 | |
9 | 3 | 9 | |
6 | 0 | 0 | |
5 | -1 | 1 | |
9 | 3 | 9 | |
7 | 1 | 1 | |
1 | -5 | 25 | |
Total | 60 | 0 | 52 |
Sum = Sum of error = 60
= 0
= 52
Standard Deviation =
=
= 2.2804
S =
=
= 2.4037
Mean
=
Median = Middle most value that are arrange in ascending order = 5th & 6th value
taking the average of it = ( 5 + 6 ) / 2 = 5.5
Median = 5.5
Mode = Is the value occure most frequently = 5 ( 5 occurs 4 times in the data)
Minimum score = 1
Maximum score = 9
Range = Maximum - Minimum = 9 - 1 = 8
Comparison Table | 8 - hour | 12 - hour |
Mean error | 5 | 6 |
Median error | 4.5 | 5.5 |
Mode error | 4 | 5 |
SD of error | 1.8974 | 2.2804 |
Minimum error | 2 | 1 |
Maximum error | 8 | 9 |
Range of error | 6 | 8 |
Overall 8 - hour shift is better than 12 - hour shift, in term of performance.
In this project you will: hand in a formal memo with worksheet attached (showing your work,...
Question 1.
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b. Include a table that shows the average and the other
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c. Comment on which network is doing best.
| Η 1 CBC 15.6 AB DE BBS...
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Can you please help me with my homework
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Due Since Yesterday, need it ASAP please!
Data is there already. if you can't do it don't mess
with it. You asked the same thing yesterday.
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Answers 3-9. Explain work.
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