(a) Since AB is perpendicular to the direction of electric field, A and B are equipotential points. So, VB - VA = 0
(b) VC - VB = E * dCB = -1000 * (4 * 1 * 10-2) = -40 V
(c) Since VA = VB, we have,
VC - VA = VC - VB = -40 V
9 A uniform electric field E = - 1000 N/C i is shown in the figure...
9 A uniform electric field E = - 1000 N/C i is shown in the figure below. The value for L = 1.0 cm. L What is the difference in electric potential, Delta V = V_B - V_A, between points A and B? What is the difference in electric potential, Delta V = V_C - V_B, between points C and B? What is the difference in electric potential, Delta V = V_C - V_A, between points C and A? While...
A uniform electric field of magnitude 1,000 N/C points in the negative y-direction. Calculate the electric potential difference V_B-V_A between the points A =(1cm, 2cm) and B = (3cm, 1cm). VB-VA = 10V VB-VA = 20V VB-VA = 30V VB-VA = -10V VB-VA = -20V VB-VA = -30V
4000 V O 1000 v QUESTION 8 If the electric field is 12 V/m in the positive x-direction, what is the potential difference between the origin, (0, 0), and the point (3.0 m, 4.0 m)? O 48 V with the origin at the higher potential 。48 V with the origin at the lower potential 36 V with the origin at the higher potential O 36 V with the origin at the lower potential 5.55556 points QUESTION 9 A 6.0 V...
A uniform electric field of magnitude E=4.2N/C points, as illustrated in the figure below, along the negative x axis. The x and y-coordinates of points A, B, and C are shown in the figure. a) Determine the differences in potential between points A and B, points C and B, and points C and A. (b) What is the change in the potential electric energy of the system if a positive charge of 2nC is moved from B to C? How...
A +4.0 mu C-point charge and a -4.0-mu C point charge are placed as shown in the figure. What is the potential difference, V_A - V_B, between points A and B?
The electric potential in a region of uniform electric field is -1000 V at x = -1.80 m and + 2000 V at x =+ 1.70 m . What is E x ?
1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗ directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...
Consider a uniform horizontal electric field of 50 N/C directed toward the east. If the electric potential measured at a given point is 80 V, what is the potential at a point 1.0 m directly west of that point? (the answer is NOT 30V).
19.17 Electric Potential in a Uniform Electric Field What is the electric field strength between two parallel conducting plates if the plates are separated by 2.30 mm and a potential difference of 4.9x 10 V is applied? Does the electric field strength exceed the breakdown strength for air (3.0x10° V/m)i? Yes No Submit Answer Tries o/10 How close together can the plates be with this applied voltage? Submit Answer Tries 0/10
In the region shown in the image, there is a uniform electric field of magnitude 52.5 N/C which points in the positive y-direction. Points 2, 3, and 4 are all 0.497 m away from point 1, and the angle o = 46.4". Calculate the potential differences AV between each indicated pair of points. V2 - V1 = 26.09 V- Vi = 0 Va-V1 = 18.90 12-V= -44.99