Question

4000 V O 1000 v QUESTION 8 If the electric field is 12 V/m in the positive x-direction, what is the potential difference between the origin, (0, 0), and the point (3.0 m, 4.0 m)? O 48 V with the origin at the higher potential 。48 V with the origin at the lower potential 36 V with the origin at the higher potential O 36 V with the origin at the lower potential 5.55556 points QUESTION 9 A 6.0 V battery maintains the electric potential difference between two parallel conducting plates separated by 1.0 mm. What is the electric field between the plates assuming a uniform field? Save Save All Answers Click Save and Submit to save and submit. Click Save All Answers to save all answers

Answer 1

Answer: 36 V with the origin at the higher potential

The potential difference between two points in a uniform electric field is given as the product of the strength of electric field and the distance moved parallel to the field. Mathematically we may write,

$\bigtriangledown V = \overrightarrow{E}. \overrightarrow{ds}$

where,

• V is the electric potential
• E is the electric field
• ds is the distance moved

In the given problem, the electric field is directed in the positive x-direction. Thus only the distance moved in the x-direction (parallel to field) will contribute to the potential whereas the distance moved in y-direction (perpendicular to field) will not.

Thus,

$\bigtriangledown V = 12*3\\ = 36\ V$

Electric field always points from a higher potential to lower potential which means that origin (0, 0) will be at a higher potential than that of point (3.0 m, 4.0 m)