here,
edge length, a = 380 cm = 3.8 m
1) energy stored in the capacitor = 0.50 * C * V^2
energy stored in the capacitor = 0.50 * 8.854 *10^-12 * 3.8^2/(0.001) * 12^2
energy stored in the capacitor = 9.2 *10^-6 J = 9.2 uJ
the energy stored in the capacitor is 9.2 uJ
Problem 24 1 A parallel-plate capacitor has square plates that have edge length equal to 3.80x102...
An air-filled, parallel-plate capacitor with area A and gap
width d is connected to a battery that maintains the plates at
potential difference V.
1. The plates are pulled apart so that the gap is 2 times wider,
while they remain in electrical contact with the battery terminals.
By what factor Uelectric,f/Uelectric,iUelectric,f/Uelectric,i does
the potential energy of the capacitor change? (Express your
answer to two significant figures.)
2. By what factor
Uelectric,f/Uelectric,iUelectric,f/Uelectric,i does the potential
energy of the capacitor change...
A parallel plate capacitor has square plates with sides of length 11 cm. The distance between the plates is 2 mm. The plates are charged up to 20volts. Part A What is the electric field between the plates? Express your answer using three significant figures. Electric field = N/C Part B What is the amount of charge on each plate? charge = C Part C What is the capacitance? Capacitance = μF Part D What is the energy stored by...
A parallel plate capacitor is constructed with plate area of 0.80 m2 and a plate separation of 0.10 mm. When it is charged to a potential difference of 12 V, the charge stored on it is = micro C. A parallel plate capacitor is constructed with plate area of 0.40 m2 and a plate separation of 0.10 mm. When it is charged to a potential difference of 12 V, the charge stored on it is= micro C. A parallel-plate capacitor...
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm each, spaced 3.7 mm apart. It is connected to a 10-V battery. If the capacitor remains connected to the battery and the plates are pulled apart to a separation of 7.7 mm . a) What is the new capacitance? b) What is the new charge on each plate? c)What is the new electric field between the plates? d) What is the new energy stored...
The plates of a parallel-plate capacitor each have an area of 0.1 m2 and are separated by a 1 mm thick layer of glass. The capacitor is connected to a 11 V battery. (The dielectric constant for glass is 5.) a) Find the capacitance. b) Find the charge stored. c) Find the electric field between the plates.
A parallel plate capacitor is comprised of two metal plates with area A and separated by distance d. This parallel plate capacitor is connected to a battery with voltage AVo. Your answer should depend on A, d, ΔVo, and any other physical constants a. Determine the charge stored on the plates of the capacitor and the energy stored in the capacitor b. Determine the strength of the electric field between the plates of the capacitor c. An experimenter has five...
A parallel-plate capacitor has 2.00 cm2 plates that are separated by 5.00 mm with air between them. If a 12.0 V battery is connected to this capacitor, how much energy does it store?
A parallel plate capacitor of plate area A square meters is connected to a 10-volt battery. The plates are moved apart with constant speed v0, while still connected to the 10-volt battery. Find the instantaneous rate of change of potential energy stored in a capacitor when the plates are x meters apart.
16. A parallel plate capacitor has dimensions 39 cm 43 cm. The plates are separated by a l 15-mm thickness of paper (dielectric constant K 3.7) What is the charge that can be stored on this capacitor, when connected to a l 4-V battery? (885 10-12 c2Nm2
A parallel-plate capacitor with plate area 4.0cm^2 and air gap separation 0.50mm is connected to a 12-V battery, and fully charged. The battery is then disconnected. Part A- What is the charge on the capacitor? Express your answer to two significant figures and include the appropriate units. Answer: 8.5 x 10^11 C. Part B- The plates are now pulled to a separation of 0.75 mm. What is the charge on the capacitor now? Express your answer to two significant figures...