Homework Answers
R2 and R3 are in series and their combination is parallel to the R1
So
Equivalent resistance is given by
Req=[R1(R2+R3)]/(R1+R2+R3)=[40(5+15)]/(40+5+15)=13.33 ohm
Total current
I=V/Req=2/13.33=0.15 A=150mA
Current through R2=I2=150 -50=100mA=0.1 A
So
Power dissipated in R2=(I2)2R2=(0.1)2(5)=0.05 Watt
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