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9. What is the magnetic field at P due to the current / in the wire shown below if I=2 A, a= 4 cm and b=6 cm? a U —

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Answer #1

Magnetic field=\muo*i/4(1/a-1/b), where \mu o is permeability in free space, i is current, a and b are the indicated radius.

Here,i=2 A, a=4 cm=0.04 m, b=6 cm=0.06 m.

So, magnetic field=4π*10^-7*2/4*(1/0.04-1/0.06)=5.236*10^-6 T.

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