26) Calculate the pH of 0.0385 M hypochloric acid [HClO]. [Ka= 3.0*10-8]
explain answer please and show work
HClO ? H+ + ClO-
Initial 0.0385 0 0
after dissocialtion 0.0385-x x x
Since Ka is very small so x will also be small.
So, 0.0385-x ?0.0385
Ka = [ClO-][ H+]/[ HClO]
3*10^-8 = x*x/0.0385
x = squareroot(0.0385*3*10^-8)
x = 3.40*10^-5
pH = -log[H+]
= 4.46
26) Calculate the pH of 0.0385 M hypochloric acid [HClO]. [Ka= 3.0*10-8] explain answer please and...
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