A 50-Ω resistor is connected across a battery, and a 26-mA current flows. When the 50-Ω resistor is replaced with a 23-Ω resistor, a 43-mA current flows.
A) What is the battery's voltage?
B) What is internal resistance?
I need the correct answers to 2 significant figures.
here by using ohms law
V = I * R
V = 26 * (R + 50)
V = 43 * (R + 23)
26 * (R + 50) = 43 * (R + 23)
17 *R = 311
R = 18.3 ohms
then by putting the values of R
V = 26 * ( 18.3 + 50)
V = 1775.8 * 10^-3 volts
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