Given sigma={a, b} And languages L1, L2 contain in sigma^* I need to prove/disprove the following claim:
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Given sigma={a, b} And languages L1, L2 contain in sigma^* I need to prove/disprove the following claim:
For Language L1 and L2 prove or disprove (L1 union L2)*=L1* intersection L2*
Which of the following languages are regular. Prove (by providing a regular expression) or disprove. a. L1 = {ai bj ck dl | (i + j)mod 2 = (k + l)mod 2 , i, j, k, l ≥ 0} b. L2 = {ai bj ck dl | (i + j) = (k + l), i, j, k, l ≥ 0}
disprove that the given lan 4. [20 Points For each of the following languages, prove or guage is regular (a) L1www e {a,b}*} {w w E {a, b}* and no two b's in w have odd number of a's in between}. (b) L2 (c) L3 a" (d) L4 vw n = 3k, for k > 0}. a, b}*} disprove that the given lan 4. [20 Points For each of the following languages, prove or guage is regular (a) L1www e...
Prove that If L1 is linear and L2 is regular, L1×L2 is a linear Language.
a) if L1 is recognisable but not decidable, L2 is decidable but not recognisable, then prove L1 U L2 is undecidable? b) if L1 is recognisable but not decidable, L2 is recognisable but not decidable, then prove L1 U L2 is undecidable?
Automata, Languages and Computation Using the languages L1 = { (10)* 1(1+0) + (10)*} and L2 = { a(a*) }, construct an ei NFA that accepts the concatenation of the languages L1L2. Using the languages L1 = { (10)* 1(1+0) + (10)*} and L2 = { a(a*) }, construct an ei NFA that accepts the concatenation of the languages L1L2.
For each of the following statements, where L1, L2, and L are languages over some alphabet Σ, state whether it is true or false. Prove your answer. • ∀L,(∅ or L+) = L∗ • ∀L1,L2,(L1 or L2)∗ = (L2 or L1)∗
2. If L1 and L2 are regular languages, which of the following are regular languages? Provide justification for your answers. a. L1 U L2 b. L1L2 c. L1 n L2
If L1 and L2 are Regular Languages, then L1 ∪ L2 is a CFL. Group of answer choices True False Flag this Question Question 61 pts If L1 and L2 are CFLs, then L1 ∩ L2 and L1 ∪ L2 are CFLs. Group of answer choices True False Flag this Question Question 71 pts The regular expression ((ac*)a*)* = ((aa*)c*)*. Group of answer choices True False Flag this Question Question 81 pts Some context free languages are regular. Group of answer choices True...