One wants to maximize the stiffness of the truss by minimizing the size of the displacement vector, or . Young’s modulus is E, and the force P>0. The design variables are the cross-sectional areas of the bars. The volume of the truss may not exceed the value V0. Defining
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One wants to maximize the stiffness of the truss by minimizing the size of the displacement vector,
Example3.3 One wants to maximize the stiffness of the two-bar truss in the figure by minimizing its compliance . The truss is subjected to the force . The volume of the truss may not exceed the value , and the magnitude of the stresses (both in tension and compression) are not allowed to exceed the value ,where is...
Solve the following truss problem. All truss members are ANSI 2x2x0.25 hollow square tubes (with rounded corners) for which the cross-section area is A-1.5891 in2. The material has a modulus of E-29E6 psi. Length of element 1 and 5 is L-20 inches, and length of element 3 and 6 is 2L 40 inches. 7 5 6 P-1000 lb 2. 1. Solve in an Excel spreadsheet using the truss element. Note that there are only four different element stiffness matrices (look...
The below truss is made from three bars of the same steel material, all of which have circular cross sections with different diameters. The Young modulus of steel is E= 200 GPa, and yield stress of steel is Gyöeld=200 MPa (in both tension and compression). The force P=7 kN is applied at point C as shown (see Figure 4). All bars are pin connected at their ends. (a) Determine the minimum diameter of the bars so that buckling will not...
a. Compute the total stiffness matrix [K] of the assemblage shown in Figure 3-1 by superimposing the stiffness matrices of the individual bars. Note that should be in terms of A. As, A, E, E E, L. and L. Here A, E, and are generic symbols used for cross-sectional area modulus of elasticity, and length, respectively Figure P3-1 Now let As - Ag-A-A.E E, E E and L-L L -L nodes 1 and 4 are fixed and a force Pacts...
Use MAT:AB to code 650:231 M.E. Computational Analysis and Design Finally, give the member force by (see (8) in Project_2_Suppliment) PART A 15 Pts.] Consider the truss given by Fig. 2. The height of the truss is 3 ft. The cross sectional area and Young's modulus of each bar is a-I in, and E-30 Mpsi (106 lb/in2), respectively. The symbol # for the applied load indicates the unit of lb. The truss is supported by a pin at node 6...
1. The following is a one-layer truss structure fabricated from aluminum tubing with outside diameter and wall thickness as 0.4 inch and 0.05 inch, respectively. The Young's modulus and Poisson's ratio for aluminum are E= 10 x 10°psi, v=0.33, respectively. The applied load P is 60 Ib. Please answer = 60° B Ra all Cled URb The internal force for member AC is: -30 lb 34.6 lb 30 lb -34.6 lb Question 2 1 points Save Answer 1. The following...
A 3 m rigid bar AB is supported with a vertical translational spring at A and a pin at B The bar is subjected to a linearly varying distributed load with maximum intensity g Calculate the vertical deformation of the spring if the spring constant is 700 kN/m. (ans: 21.43 mm) 2. A steel cable with a nominal diameter of 25 mm is used in a construction yard to lift a bridge section weighing 38 kN. The cable has an...
Problem 3. Assume that the house is 9 feet tall, has pipe size of 20 in. and post height is 40 ft. See the chart below for the cross-sectional properties of your pipe. Assume a wind pressure of 30 psf. a. Calculate the force/foot of pipe by multiplying the wind pressure by the diameter of the pipe. The uniform load is 1200 on the pipe in lb/ft. b. Calculate the resultant force caused by the wind on the house. Treat...
i have also attached the solutions. could you please explain step by step what they are doing. especially the bit in part (a) where they do x/d Question 2 Picture it. It's 5 o'clock on Friday and at the end of a long week all Dave wants to do is go home. But his boss has other ideas; he tells Dave that he can go once he has designed the tension reinforcement for the beam in Figure 2. a) Design...