Question

Exercise 1: Draw a free body diagram for M. what does the tension turn out to be?

please chose one: [1] Mg [2] mg [3] (M+m)g [4] (M-m)g

Exercise 2: Draw a free body diagram for m. what does the mass ratio, m/M, turn out to be?

please chose one: [1] cos [2] tan [3] sin [4] 1

Exercise 3: What is the radius of the circle in which m moves? Use the free body diagram for m to write down Newton's 2nd law for m in the horizontal direction. Assume m is moving at speed V.

please chose one: [1] L [2] L*cos [3] L*sin [4] L*tan

Answer 1

(a)the downward force on the Mass 'M"
will be Mg which is equal to tension T
T = Mg
(b)When we see the FBD of mass m
then we come to know that
TSin(theta) = mg
therfore
m/M = sin(theta)
(c) If L is the length of the string then radius of the circle is Lcos(theta)
In horizontal direction
TCos(theta) = mV²/r where V is the Velocity of mas and r is the radius of the circle.