Question

What is the amount of air mass that passes through a wind turbine's swept area per minute if the turbine has 45 m long blades and the air flux is 12 kg/(m´s)? O 76,300 kg/min 0 1,458,000 kg/min O 4,580,400 kg/min O 3,014,400 kg/min

wind energy question 9

Answer 1

Swept area of the wind turbine, is the area which the rotor blades make upon one complete rotation with radius being the size of the rotor blade of the turbine.

∴ swept area = $\pi$ *R²

= $\pi$ * 45²

= 6361.73 m²

also air flux is given = 12 kg/ m².s

so , mass of air swept per second within the swept area = 12 x 6361.73

= 76340.70 Kg/s

∴ finally, amount of air mass that passes through the wind turbine's swept area per minute = 76340.70 x 60

= 4,580,442 Kg/ min

the actual answer in the option given is 4,580,400 kg/min which is almost close to the calculated answer.

so the correct answer is C) 4,580,400 kg/min