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1. If you are tossing a fair coin 4 times and X - the absolute difference between the number of HEADs and the number of TAILs
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Answer #1

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pmf of X is as follows:

P(X=0)=P(2 heads and 2 tails)=4C2 (0.5)2(0.5)2 =0.375

P(X=2)=P(3 heads and 1 tails)+P(1 heads and 3 tails)=4C3 (0.5)3(0.5)1 +4C3 (0.5)3(0.5)1 =0.25+0.25=0.50

P(X=4)=P(4 heads and 0 tails)+P(0 heads and 4 tails)=4C4 (0.5)4(0.5)0 +4C0 (0.5)0(0.5)4=0.0625+0.0625=0.1250

x f(x) xP(x) x2P(x)
0 0.3750 0.000 0.000
2 0.5000 1.000 2.000
4 0.1250 0.500 2.000
total 1.500 4.000
E(x) =μ= ΣxP(x) = 1.5000
E(x2) = Σx2P(x) = 4.0000
Var(x)=σ2 = E(x2)-(E(x))2= 1.7500
std deviation=         σ= √σ2= 1.3229

from above mean =E(X)=1.5

and std deviation =1.3229

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