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The complex exponential Fourier series of a real even signal has non-zero coefficients for non- negative k given by k a_k 0 2

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Answer #1

Eneig in Third harmonic (23)²+(2+3) (0.5) + 10.5) Ezk 0.5 Joule harmonic 4th Energyain = (2-4)² + (ate 603+ * Euk = e Joule W

Poate Fourier series in term of Sin and Casine. (an Cash Wott bn Sin wont) f1t) = Got n=1 - bnão . 3 eos 3nt to flt) = 297 ☆

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