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Provide a scheme of Benzoic C6H5-COOH with water (acid ionization expression). The pKa is 4.20 and...

Provide a scheme of Benzoic C6H5-COOH with water (acid ionization expression). The pKa is 4.20 and the molar mass is 122.1g.

Provide a scheme of Salicylic C6H4(COOH)(OH) with water (acid ionization expression). The pKa is 2.98 and the molar mass is 138.1g.

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Answer #1

acid ionisation expression : C6H5COOH (aq) + H2O (l) <--------------------> C6H5COO-(aq) + H3O+ (aq)

ionization constant = Ka = [C6H5COO-] [H3O+] / [C6H5COOH]

acid ionisation expression C6H4(COOH)(OH) (aq) + H2O (l) <-------------> C6H4(COO-)(OH) (aq) + H3O+

ionization constant = Ka = [C6H4(COO-)(OH)] [H3O+] / [C6H4(COOH)(OH)]

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