C5H12(l) + 8O2(g) ------>5CO2(g) + 6H2O(l)
1 mole of C5H12 are burned in excess of oxygen to form 6 moles of H2O
72gm of C5H12 are burned in excess of oxygen to form 6*18gm of H2O
41.7gm of C5H12 are burned in excess of oxygen to form = 6*18*41.7/72 = 62.55gm of H2O
Consider the following unbalanced chemical equation. C_5H_12(l) + O_2(g) rightarrow CO_2(g) + H_2O(l) If 41.7 grams...
Consider the following unbalanced chemical equation. C5H12(/) + 02(g) → CO2(g) + H2O(/) If 37.2 grams of pentane (CH12) are burned in excess oxygen, how many grams of H20 will be produced? g H20
Consider the unbalanced the equation given below for the of below CaH_33 (g) + O_2 rightarrow CO_2(g) + H_2O Balance the equation and determine how many moles of O_2 are required to react completely with 4.9 moles of CaH_25? Consider the following general chemical equations 2A + 4B rightarrow 3C What is the theoretical yield of C when each of the initial quantities of A and B is allowed to react in the general equation a. 1.8 moles of A:...
Consider the reaction represented by the unbalanced equation NH_3 + O_2 rightarrow NO + H_2O. For every 6.94 mol of NH_3 that reacts, mol of O_2 is required. 8.68 6.94 27.76 5.55 none of these
When the following equation is balanced, the coefficients are__C_8H_18 + O_2 rightarrow CO_2 + H_2O 2, 3, 4, 4 1, 4, 8, 9 2, 12, 8, 9 4, 4, 32, 36 Of the reactions below, which one is got a combination reaction? C + O_2 rightarrow CO_2 2Mg + O_2 rightarrow 2MgO 2N_2 + 3H_2 rightarrow 2NH_3 CaO + H_2O rightarrow Ca(OH)_2 2CH_4 + 4O_2 rightarrow 2CO_2 + 4H_2O
Hello , please help me to answer the following 3 questions: Fe_2O_3(s) + CO_(g) rightarrow Fe_(S) + CO_2(g) (unbalanced) Calculate the number of grams of CO that can react with 0.517 kg of Fe_2O_3. Consider the following equation: N_2(g) + 3 H_2(g) rightarrow 2 NH_3(g), how many molecules of ammonia are produced when 36.5 liters of hydrogen react at STP (in excess nitrogen)? Given C_3H_8 + O_2 rightarrow CO_2 + H_2O (balance the equation) When 25.0 grams of C_3H_8 react...
Consider the following reaction: Ca(s) + 2 H_2O(l) rightarrow Ca(OH)_2(s) + H_2(g) Calculate the heat of reaction based on the following information: 2H_2(g) + O_2(g) rightarrow 2 H_2O(l) DeltaH = -572 kJ/mol CaO(s) + H_2O(l) rightarrow Ca(OH)_2(s) DeltaH = -64 kJ/mol CaCO_3(s) rightarrow CaO(s) + CO_2(g) DeltaH = +178.1 kJ/mol 2 Ca (s) + O_2(g) rightarrow 2 CaO(s) DeltaH = -1270 kJ/mol 13. Acetylene is used in blow torches, and bums according to the following equation: 2 C_2H_2(g) + 5...
Help would be greatly appreciated Consider the following reaction: S(s, rhombic) + O_2 (g) rightarrow SO_2(g) Use standard heats of formation from Gum Dahl 'Chemical Principles' 7th ed. Appendix Four pp. A19 - A22 How much heat is evolved when 2.886 times 10^2 g of S(s, rhombic) is burned in excess oxygen. Answer to 4 sig figs. How much heat is evolved when 3.000 times 10^2 g of SO_2(g) is produced from the combustion of S(s, rhombic). Answer to 4...
Consider the reaction B_2H_6(g) + 3 O_2(g) rightarrow B_2O_3(s) + 3 H_2O(g) Delta H= -2035 kJ/mol Calculate the amount of heat released when 54.4 g of diborane is burned, heat released = kJ
4.20 If 3.365 g of ethanol C_2H_5OH(l) is burned completely in a bomb calorimeter at 298.15 K, the heat produced is 99.472 kJ. a. Calculate Delta H degree_ for ethanol at 298.15 K. b. Calculate Delta H degree_ of ethanol at 298.15 K. From the following data, calculate Delta H degree_ for the reaction CH_3COOH(g) rightarrow 2 H_2O(g) + 2 CO_2(g): Delta H degree _g (kJ mol^-1) CH_3COOH(l) + 2 O_2(g) rightarrow 2 H_2O(l) + 2 CO_2(g) -871.5 H_3O(l) rightarrow...
How many grams of oxygen are formed when 6.21 moles of KOH are formed? 4 KO(s) + 2 H_2O(l) rightarrow 4 KOH(s) + O_2(g) 19.9g 27.9g 49.7g 3.59g 11.7g Consider the following balanced reaction. How many grams of water are required to from 75.9g of HNO_3? Assume that there is excess NO_2 present. Molar masses: H_2O = 18.02g. HNO_3 = 63.02g. 3 NO_2(g) + H_2O(l) rightarrow 2 HNO_3(aq) + NO(g) 38.0g 21.7g 43.4g 10.9g 26.5g A 12.39g sample of phosphorus...