Question

The city's transportation department is interested in studying the relationship between the outside temperature and the number of passengers that ride the main bus line in order to better serve their customers. The manager recorded the temperature at the beginning of the hour and then had a bus driver record the number of passengers that boarded the bus throughout the hour. Calculate the Pearson's correlation coefficient for the dataset below and interpret what that means. temperature passengers 77.1 26 77.1 11 25 69.7 71.4 76 75.2 43 26 78 37 23 78.3 69.7 71.7 28 31 0 1) The correlation is -0.228. There is a weak negative linear association between temperature and passengers. The correlation is -0.228. There is a strong negative linear association between temperature and passengers . The correlation is -0.228. There is a weak positive linear association between temperature and passengers. The correlation is 0.228. There is a weak positive linear association between temperature and passengers. The correlation is 0.228. There is a weak negative linear association between temperature and passengers .

Answer 1

1) The correlation is -0. 228.There is a weak negative linear association between temperature and passenger.

x_ y_(x-px) (Y-Myl_(X=Px)? (BY-PX? (X- PAY-Py) z ? 77.1 26 2 .680 77.1 l . 2.680 69.7 25 -4.720 7104 43 -3.020 76 26 1.580 75.2 43 0.780 78 37 3.580 783 23 3.880 | 69.7 28 -4.720 71- 731 7442 293 -3.3 -18.3 -4.3 13. 7 -3.3 13.7. 7.7 -6.3 -1.3 .7.182 7.182 22.278 9 .120 2.49.6 0.608 12.816 15.054 22.278 7398 106.416 10.89 334.89 18.49 187.69 10.89 187.69 59.29 39.29 B64.69 2.89 854. -8.844 -49-044 20.0296 -41.374 -5.214 10.686 27.566 -24.444 6.136. - 4.624 -68.86 -2.720 1.7 Mean of x, px 74.42 EČx-px)= SSx = 106.416 V Mean of Y, By = 29.3 EC-jºy)2 = SSy = 854-1 *(x-px) (Y-Py) = SSxy = -68.86. .: looselateon coeff. o= (x-px) (Y-Py) = -68.86 TEX-?ELY-Py)? V106.416 X 854./ -0.2284 y= -0.2284