Question

A sample of oxygen gas has a volume of 2.61 L at 21°C. What volume will it occupy at 147°F if the pressure and number of mol are constant? Enter your answer in the provided box.

Answer 1

Initial volume (V)= 2.61 L Inital temperature to - 21+ 273 = 2quk Final volume (V2) = ? firal temperature = 147°F = (1970f-32) x 5 + 273.15 - 337.04 k we know vxt con ug - 72 ūT v2 = (W) ( 72 ) - (2.612) 337.04k) 337.ouk ( 294. ¢ ) = 2.994 Final volume = 2.99L COM 3.00L

Answer 2

ANSWER :

As per gas law, P V = R T 

R is gas constant and if P remains constant, then,

V / T = constant 

=> V1 / T1 = V2 / T2

Now, 

V1 = 2.61 L

T1 = 21 + 273 = 294 ºK

V2 = ?

T2 = (147 - 32)*5/9 + 273 = 336.89 ºK

So, 

V2 = V1 * T2 / T1 = 2.61 * 336.89 / 294 = 2.99 L (ANSWER).