7. An object is placed 10.0 cm in front of a lens. An upright, virtual image...

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Answer 1

Answer #1

U=-10cm 20-30 cm $ te te Lett Ě - 30 to - 1 = (30+10) F (30)(10) f = 307 40 I f = 7.5 cm 6 m = v = 20 = -3 [magnification]

Answer 2

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