Question

Write a function with two input parameters: an array of numbers and the size of the array (the number of elements). The function should return the count of even numbers in the array. For example, if the input to the function is the array [3, 2, 45, 56, 12], the function would return the integer 3. Use the following function header:

int countEvens(int nums[], int size) {

}

Answer 1

#include<stdio.h>
#include<conio.h>

int countEvens(int nums[], int n)
{
   int i,c=0,b;
  
   for(i=0;i<n;i++)
   {
       b=nums[i]%2;
       if(b==0)
           c++;
   }
   return c;
}

void main()
{
   int cc,a[5],i;

   for(i=0;i<5;i++)
   {
       printf("\nEnter an Integer:");
       scanf("%d",&a[i]);

   }
   cc=countEvens(a, 5);
   printf("Number of Even numbes are=%d",cc);
   getch();
}