Two charges Q1 (= +6 μC) and Q2 (= –2 μC) are brought from infinity to positions on the x-axis of x = –4 cm and x = +4 cm, respectively. How much work was done in bringing the charges together?
SOLUTION :
Q1 = 6 µ C = 6 * 10^(-6) C
Q2 = - 2 µ C = - 2 * 10^(-6) C
Distance between Q1 and Q2 , r = 4 - (-4) = 8 cm = 0.08 m^2
W = k Q1 Q2 / r
Where k = 9.0 * 10^9 Nm^2 / C^2
So,
W
= 9.0 * 10^9 * (6 * 10^(-6)) * (- 2 * 10^(-6) / 0.08 (N-m)
= - 1.35 N-m
= - 1.35 J (ANSWER)
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