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A charged particle is held at the center of two concentric conducting spherical shells. Figure (a) shows a cross section. Fig

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Answer #1

The flux of the particle is given by , = -1.80,= -8.10% 10%Nm2/C. As €0 = Lenc then qp = 8.85 x 10-12.-8.1x 105 = - 7.17 MCOutside of shell A, the flux takes the value A That gives us the total charge enclosed inside A: 89, =3.60x 105Nm2/C. Genc =Finally, the flux outside of shell B is 08 = -.40, = -1.80 x 105Nm2/C. By the same process: Genc = 8.85 x 10-12.-1.8 x 10 = -(a) -7.17μC (b) +10.4 μC (c) -1.64μC

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