Homework Answers
P(English Class) = 0.60
P(Statistics class ) = 0.75
P(English class or Statistics class) =0.90
P(English class or Statistics class ) = P(English Class) +P(Statistics class ) -P(English class and Statistics class)
Substitute given values into above addition rule of probability.
=> 0.90 = 0.60 + 0.75 - P(English class and Statistics class)
=> P(English class and Statistics class)=0.45
The probability that a randomly selected student is taking an English class and is not taking a Statistics class)
=0.60-0.45.................
=0.15
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