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ef count_common_occurrences(word1, word2): (str, str) -> int Given two strings, word1 and word2, return how many characters in word1 are letters that also occur in word2. You can assume all characters in the given string are lowercase. Also, spaces do not count as a common character. Algorithm: - Go through each character in word1, one by one. If this character occurs in word2, then add 1 to the count. Return total count after youre done going through the characters. > count common occurrences(bob y, bobbette z >>> count common occurrences(bobbette z, bob y) 4
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Answer #1

Here is code:

def count_common_occurrences(word1,word2):
counter = 0
# loop through character in word1
for i, c in enumerate(word1):
# check if c is aplhabet and c contains in word2
if(c.isalpha() and word2.find(c) != -1):
counter = counter + 1 # incremenet counter
return counter
  
print(count_common_occurrences('bob y','bobbette z'))
print(count_common_occurrences('bobbette z','bob y'))

def count common occurrences (word1,word2): countere # loop through character in word! for i, c in enumerate(word1): # check

Output:

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