Question

Bianca uongowns Pre-Laboratory Questions 125 g of har d e is 20 "C. 100 ml de 700 ml. of processed solutions 2. Write the dissociation reaction and K, expressions for the following salts: .. Iron(II) carbonate b. Aluminum sulfate

Answer 1

mass of Ba(OH)2 = 2.65 g volume of water = to me In to all water there is 2.65 g of Ba(OH)2 @ So, In 100 ml coater there is (2.65 x108) g of Ba(OH)2 = 3:7857 g of Hence ва (он), solubility in a poome) is 3.7857. 6 In 1000 ml (14) wat er there should be 24 x lon) = 37.8579 Of - Ba(OH) Hence solubility in (9/) is 37.857912 @ In One Lithe solution there is 37.8579 of Ba(OH)2 Molar mass of Ba(OH)2 is 171.34 g/mol. Now, 37.857 g of Ba(OH)2 = (37.857 rol of - 0.2209 Ba(OH) 171.34 /

So, in one litre solution there is 0.2209 mal of Ba(OH)2 Hence melarity of Solution is 0.2209 (M) 2+ . ② » Fe(CO3)(s) – fer can) + co (ar) (smelk) (s) moll (5) melk Ksp = [Fe²+] . [co ] If solubility of recoz is s mollh then Ksp - Sts = 5² So ksp = 52 © A12 (504), 0) = 2 AŽ" (92) + 3 số cz) e Small I kap = [ 4.3+)? [ So 273 1. If solubility of Ala (59) iss mol/l then I kap = (25) ² x (85) ² = 45 x 275² ar kop = 108 st L (25)