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A soil profile consisting of 3 layers is shown in Fig. 3. Answer the following V. questions: (20 pts) Layer 1 HI-5 m, e-0.7,

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oll Tivem H = 5m E e=0.7 Gs = 2.69 BB H₂ = 8m e=0. 55 Gs 2.7 . e2 = 38% H₂= 3m solution BULL X + e= 0.7 Hi= 5 Gg = 2.69 for A12.7 + 1x 0.55 x 9.81 L 1+0.55 Yete = {2-*****0:55*3.91 Yste = 20.57 kN/ma For layer 3 . o =38% e = 1.2 s=1 Se=who Gs = 1-2xat point C T= Yd, x H + Ysetz X H₂ M = Yw Hz = 9.81x8 d= 24 2:16-78048 = 163-68 RAMZ = 15.52x 5 + 20.57X8 = 78.4 = 242.16 KW2 Changes in effective etrus at point c 2 (A) When water table drops am _ Due to drop in water table by 2 m in layer 2, the s(B) if Water table Rises to 3m Above point A. After Rising of Water table, the soil of layer 1 will also be saturated, So y s

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