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A 100-ton refrigeration system operates on the simple vapor compression refrigeration system with R-22 as the...

  1. A 100-ton refrigeration system operates on the simple vapor compression refrigeration system with R-22 as the working fluid.  The evaporator pressure is 2 bar and the condenser pressure is 30 bar.  The refrigerant leaves the compressor at 160oC.

1 ton of refrigeration = 3.517 kW

  1. Determine the cooling load, in kW.
  2. Plot all five points (1, 2s, 2a, 3, 4) on the P-h diagram.
  3. Determine the power consumed by the refrigeration system, in kW.
  4. Determine the COP of the system.
  5. Isentropic efficiency of the compressor.
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Answer #1

NOTE : SINCE THE EXACT VALUES FOR R-22 REFRIGERANT IS NOT AVAILABLE IN REFRIGERATION TABLE AT GIVEN PRESSURE AND TEMPERATURE, USING LINEAR INTERPOLATION THOSE VALUES HAVE BEEN FOUND. HOWEVER IT WONT CREATE MUCH EFFECT IN SOLUTION IF ONE IS TAKING THE NEAREST VALUE AVAILABLE IN TABLE.

Vapour compression Refrigeration System @ Cooling load (Refrigeration effect cooling load = 100 ton = 100x3-513 = 351.7 kW t& 160°c hohsup @ 3oookpa = 509 kulkg From Super heated R-22 table Power consumed Spin = in. Cha-ha To find mass flow rate. h₂Now we know that R E = cooling load = no Cho-by) on 35107 = ( 394.55- 293.1258) in = 3-4676 kg/s Power consumed by System Pinr-1 = 3.4676X1.18 [ 3000x 0.0121-2008 0.1160 1.18 - 1 297.7897 kW 297.7897 x100 Isentropic efficiency Yo = 396.8684 %z = 0.75

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