It was shown in Example 21.11 (Section 21.5) in the textbook that the electric field due to an infinite line of charge is perpendicular to the line and has magnitude E=λ/2πϵ0r. Consider an imaginary cylinder with a radius of r = 0.110 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.65 μC/m . |
Part A What is the electric flux through the cylinder due to this infinite line of charge?
SubmitMy AnswersGive Up Part B What is the flux through the cylinder if its radius is increased to r= 0.530 m ?
SubmitMy AnswersGive Up Part C What is the flux through the cylinder if its length is increased to l= 0.940 m ? |
(A) From Gauss law,
total flux = Qin / e0
= ( lambda L ) / e0
= (4.65 x 10^-6 x 0.440) / (8.854 x 10^-12)
= 2.31 x 10^5 N m^2 / C
(B) By changing radius, Qin does not change hence flux will remain same.
flux = 2.31 x 10^5 N m^2 / C
(C) now Qin will change.
Qin = 0.940 x 4.65 x 10^-6 = 4.94 x 10^5 N m^2 / C
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