Question

Aof gamma ray with the energy 1225 kev, passes through malsM M, and M, with the attenuation coefficients Hi-0.1,u2-0.2 and u3 0.3 cm and thicknesses x1, and x3, see Figure 3. Assuming gamma rays travel in straight line). 3.1. Calculate the thickness, xi, 3.2. Calculate the thickness, x2 3.3. Calculate the thickness, X3 if ?? ?s l0% of the incident beam on M3 M, M M3 X2 Figure3: attenuation of the beam ?0

Answer 1

Given that A narrow beam of gamma ray with the energy 1225 kev, passes through materials M_1,M_2, M_3 with the attenuation co-efficient mu_1 = 0.1, mu_2 = 0.2 and mu_3 = 0.3 cm^-1 and Thickness x_1,x_2, and x_3. \r\n The thickness x_1: phi_1 = phi_0 e^-u_1 x_1 To reduce phi_0, by 30%: phi_1 = 0.7 phi 0.7 phi_0 = phi_0 e^-0.1 x_1 = L_n(0.7) = -0.36 cm x_1 = 0.036 cm The thickness x_2: To reduce phi by 75%: phi_2 = 0.35 phi_1 phi_2 = phi_1 e^-u_2 x_2 materialimplication 0.25 e^-0.2 x_2 -0.2x_2 = L_n (o.w) x_2 = 6.93 cm The thickness x_3: To reduce phi_2 by 60% , phi_3 = 0.4 phi_2 0.4 = e^-0.3 x 0.3 x_3 = L_n (0.4) x_3 = 3.05 m x_3 = 3.05 cm