Consider two homologous DNA sequences, GATTC and CCATG. Use the Needleman-Wunsch algorithm to find the optimal global alignment between these two sequences. Use a linear gap penalty of -4 and the substitution matrix provided below. The dynamic programming matrix is already outlined below, you just need to fill it according to the algorithm. Be sure to write out your final alignment!
here we use two matrix one is score matrix and other is trace back matrix
with the help of score matrix we fill trace back matrix and with the trace back matrix we find best optimal global alignment
given sequence is GATTC and CCATG
we make both matrix for the given sequence
score matrix
G | A | T | T | C | ||
0 | ||||||
C | ||||||
C | ||||||
A | ||||||
T | ||||||
G |
since gap =-4
fill first row and first column by keep adding gap each time with start at 0.
so now score matrix is
G | A | T | T | C | ||
0 | -4 | -8 | -12 | -16 | -20 | |
C | -4 | |||||
C | -8 | |||||
A | -12 | |||||
T | -16 | |||||
G | -20 |
for filling other box of matrix use following Dynamic Programming formula
where S(Xi,Yj) is the substitution score for residue i,j
we fill matrix accordingly
G | A | T | T | C | ||
0 | -4 | -8 | -12 | -16 | -20 | |
C | -4 | -5 | ||||
C | -8 | |||||
A | -12 | |||||
T | -16 | |||||
G | -20 |
look at how come highlighed entry
D(1,1) = max{ D(0,0)+S(C,G), D(0,1)+gap, D(1,0)+gap }
look at matrix D(0,0) =0 , D(0,1) = -4 , D(1,0) = -4 and from substitution matrix which is given in question look entry for S(C,G) = -5
now D(1,1) = max{ 0-5 , -4-4 ,-4-4} =max{-5, -8, -8} = -5
since this entry come from diagonal so fill tace back matrix with diagonal
G | A | T | T | C | |
C | dia | ||||
C | |||||
A | |||||
T | |||||
G |
trace back entry tell us corresponding score matrix come from diagonal or up or left so it is useful for find optimize global alignment
similarly fill score matrix enty and corresponding entry
score matrix
G | A | T | T | C | ||
0 | -4 | -8 | -12 | -16 | -20 | |
C | -4 | -5 | -9 | -8 | -12 | -6 |
C | -8 | -9 | -10 | -9 | -8 | -2 |
A | -12 | -8 | 1 | -3 | -8 | -6 |
T | -16 | -12 | -3 | 11 | 7 | 3 |
G | -20 | -6 | -7 | 7 | 6 | 2 |
trace back matrix
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
now look one more highlighted entry
look at how come highlighed entry
D(5,5) = max{ D(4,4)+S(C,G), D(5,4)+gap, D(4,5)+gap }
look at matrix D(4,4) =7 , D(4,5) = 3 , D(5,4) = 6 and from substitution matrix which is given in question look entry for S(G,C) = -5
now D(5,5) = max{ 7-5 , 6-4 ,3-4} =max{2, 2, -1} = 2
since this entry come from diagonal and left so fill tace back matrix with diagonal
similarly we fill whole matrix
now trace traceback matrix from right bottom index and trace it path
since right bottom entry is dia/left so we move both path let's suppose we move diagonal up means 4th row and 4th column which again has diagonal/left entry suppose we move diagonal up means 3rd row and 3rd column which has left so we move left then we are 3rd row and 2nd column which has entry as diagonal now we have 2nd row and first column which has entry diagonal and up suppose we move up so our tracing is complete...
look at trace back highlighed entry
trace back matrix
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CAATG(row) and GATTC (column) entry which is global alignment .
similarly explore all entryu from trace back matrix...
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CCAATG(row) and GGATTC (column) entry which is global alignment .
and
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CATTG(row) and GATTC (column) entry which is global alignment .
and
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CCATTG(row) and GGATTC (column) entry which is global alignment .
and
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CATGG(row) and GATTC (column) entry which is global alignment
and
G | A | T | T | C | |
C | dia | dia/left | dia | dia/left | dia |
C | dia/up | dia | dia | dia | dia |
A | dia | dia | left | left | up |
T | up | up | dia | dia/left | left |
G | dia | up | up | dia | dia/left |
so sequence is CCATGG(row) and GGATTC (column) entry which is
global alignment .
Consider two homologous DNA sequences, GATTC and CCATG. Use the Needleman-Wunsch algorithm to find the optimal...
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