Question

Assume that you have used PCR and electrophoresis to assay an Alu element polymorphism at the D1 locus on chromosome 17 in four Asian populations. When the Alu element is not present (-), the DNA fragment is 200 base pairs (bp). When the Alu element is present (+), the DNA fragment is 500 bp.

Compute the heterozygosity (H) for each population. Don’t forget to take into account the sample size of each population! Please show your work, and remember, . [4 points + 2 points for showing your work]

Population	# of individuals	200 bp fragment (-)	500 bp fragment (+)	H
Parsi	110	0.636	0.364
Rajput	104	0.693	0.308
Munda	50	0.69	0.31
Kotas	94	0.76	0.24

Answer 1

The proportion of heterozygosity = 2*p*q.

The frequency of heterozgygosity = Number of individuals * proportion of heterozygosity.

Population	# of individuals	200 bp fragment (-) / p	500 bp fragment (+) / q	2pq	H
Parsi	110	0.636	0.364	0.463008	51
Rajput	104	0.693	0.308	0.426888	44
Munda	50	0.69	0.31	0.4278	21
Kotas	94	0.76	0.24	0.3648	34