Question

If 6.77 moles of an ideal gas has a pressure of 1.61 atm, and a volume of 29.75 L, what is the temperature of the sample?

Answer 1

As we know that the ideal gas equation as

$pV=nRT$

Here p= pressure = 1.61 atm

V= 29.75 L

R = gas constant $=0.08LatmK^{-1}mol^{-1}$

T= temperature in Kelvin

n = moles = 6.77 mol

Now apply

$pV=nRT$

$\\1.61atm\times 29.75L=6.77 mol\times 0.08LatmK^{-1}mol^{-1}\times T\\ 47.9Latm=0.5416\times T\\ T=\frac{47.9}{0.5416}K\\ T=88.44K$

Hence the temperature is 88.44 K