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An electron moves in a circular path with a speed of 1.41 x 10 m/s in the presence of a uniform magnetic field with a magnitu

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Answer #1

For a charged particle moving perpendicular to magnetic field, the path executed is circular and the magnetic force provides the centripetal force for circular motion.

- Emag = m 2 => qvB = my? sm=mass tv-speed, re radius şq=charge a re mu qB 12 period To zaro = 21 (my) = 2īm = 2(9:11X10-3116

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