Question

A particular plant has a gene for flower color and a gene for height with the following phenotypes: RR: red flower TT: tail Rr, rr: white flower Tt: medium tt: dwarf If two plants (RrTt times RrTt) are crossed, how many phenotypes can be produced in F1? 1 2 4 6 9 Eye color is an autosomal (non-sex) trait. Brown eyes are controlled by a dominant allele, and blue eyes are controlled by a recessive allele. Color blindness is an x-linked recessive trait. A mother is a heterozygous with brown eyes and carrier for colorblindness. If her husband is heterozygous with brown eyes and is not color blind. What is chance for their sons to be blueeyed and color blind? 0% 6025% 12.5% 25% 50%

Answer 1

10A. option C

If two plants (RrTt X RrTt ) are crossed;

The expected phenotype are: i. ROUND and TALL

                                                ii. ROUND   and dwarf

                                               iii. wrinkle   and TALL

                                               iv. wrinkle   and dwarf.

Phenotypic ration:   9:3:3:1.

11A. option d

Cross between : carrier colour blind X normal brown eyes

                             X X^C                             X        XY                             PARENTS

                          

                                X XC    X    Y GAMETS

ON FUSION: XX       XY     X^CX      X^C Y

XX- 25% brown eyes female

XY-25% brown eyes male

X^CX -25% carrier female

X^CY - 25% colour blind and blue eye male