Using the reactions below, determine the ∆Hº for 2 N2(g) + 5 O2(g) --> 2 N2O5(g)...

Question

Question

Using the reactions below, determine the ∆Hº for 2 N₂_(g) + 5 O₂_(g) --> 2 N₂O_5(g)

N_2(g) + 3 O_2(g) + H_2(g) --> 2 HNO_3(aq) ∆Hº = -415 kJ/mol

N₂O_5(g) + H₂O_(l) --> 2 HNO_3(aq) ∆Hº = -140 kJ/mol

2 H_2(g) + O_2(g) --> 2 H₂O_(l) ∆Hº = -572 kJ/mol

Answer 1

Answer #1

Ans :

The desired reaction can be obtained by adding :

= (double of reaction 1) + (double of reverse reaction 2 ) + (reverse of reaction 3)

So using Hess's law , the enthalpy change of the desired reaction will be given as :

= 2(-415) + 2(140) + 572

= 22 KJ/mol

Answer 2

Similar Homework Help Questions

Consider the following data. 2 H2(g) + O2(g) 2 H2O(l) ΔH = -571.7 kJ N2O5(g) +...

Consider the following data. 2 H2(g) + O2(g) 2 H2O(l) ΔH = -571.7 kJ N2O5(g) + H2O(l) 2 HNO3(l) ΔH = -92.0 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3O(l) ΔH = -348.2 kJ Use Hess's law to calculate ΔH for the reaction below. 2 N2O5(g) 2 N2(g) + 5 O2(g) ΔH = _____kJ
72. Determine AHº for this reaction from the data below. N2H4(1) + 2 H2O2(1) -→ N2(g)...

72. Determine AHº for this reaction from the data below. N2H4(1) + 2 H2O2(1) -→ N2(g) + 4H2O(1) N2H4(1) + O2(g) →→ N2(g) + 2 H2O(1) A Hº = -622.2 kJ mol-1 H2(g) + + O2(g) →→ H2O(1) A Hº = -285.8 kJ mol-1 H2(g) + O2(g) —> H2O2(1) A,Hº = -187.8 kJ mol-1
Given the following equations and Ho values given below, determine the heat of reaction at 298...

Given the following equations and Ho values given below, determine the heat of reaction at 298 K for the reaction: 2 N2(g) + 5 O2(g) 2 N2O5(g) 2 H2(g) + O2(g) 2 H2O(l) Ho/kJ = -571.6 N2O5(g) + H2O(l) 2 HNO3(l) Ho/kJ = -73.7 N2(g) + 3 O2(g) + H2(g) 2 HNO3(l) Ho/kJ = -348.2

5. Given the following data: (2 H2 (g) + O2 (g) → 2 H2O (1) ro...

5. Given the following data: (2 H2 (g) + O2 (g) → 2 H2O (1) ro in each AH° = -571.6 kJ N20s (g) + H2O (1) 2 HNO3 (1) AH° = -76.6 kJ N2 (g) + 3 O2 (g) + H2 (g) → 2 HNO3 (1) AH° = -348.2 kJ a. Calculate the AHⓇ for the reaction: 2 N2 (g) + 5 O2 (g) → 2 N2O5 (g)
Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information: 2...

Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information: 2 HNO3(l) N2O5(g) + H2O(l) H = +92.0 kJ 2 N2(g) + 5 O2(g) 2 N2O5(g) H = +59.3 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3(l) H = -348.2 kJ
Calculate the Delta H formation of N2O5 (g) given the below reactions: 2NO (g) + O2...

Calculate the Delta H formation of N2O5 (g) given the below reactions: 2NO (g) + O2 (g) -> 2NO2 (g), ΔHrxn = -114.1 kJ/mol 4NO2(g) + O2 (g) -> 2N2O5 (g), ΔHrxn = -110.2 kJ/mol N2 (g) + O2 (g) -> 2 NO (g), ΔHrxn = +180.5 kJ/mol

Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change...

Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
Determine ΔrH° for the following reaction, 2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3...

Determine ΔrH° for the following reaction, 2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3 H2O(g) given the thermochemical equations below. N2(g) + O2(g) → 2 NO(g) ΔrH° = +180.8 kJ/mol-rxn N2(g) + 3 H2(g) → 2 NH3(g) ΔrH° = –91.8 kJ/mol-rxn2 2H2(g) + O2(g) → 2 H2O(g) ΔrH° = –483.6 kJ/mol-rxn a. –1178.2 kJ/mol-rxn b. –452.8 kJ/mol-rxn c. –394.6 kJ/mol-rxn d. –211.0 kJ/mol-rxn e. +1178.2 kJ/mol-rxn
Calculate ΔG0 for the following reactions at 25oC. (a) N2(g) + O2(g) → 2NO(g) ΔG0 =...

Calculate ΔG0 for the following reactions at 25oC. (a) N2(g) + O2(g) → 2NO(g) ΔG0 = kJ/mol (b) H2O(l) → H2O(g) ΔG0 = kJ/mol (c) 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l) ΔG0 = kJ/mol

For the reaction C2H4(8) + Cl2(g) — C2H4C12(1), determine A,Hº, given that 4 HCl(g) + O2(g)...

For the reaction C2H4(8) + Cl2(g) — C2H4C12(1), determine A,Hº, given that 4 HCl(g) + O2(g) — 2012(g) + 2 H2O(1) AH° = –202.4 kJ mol-1 2 HCl(g) + C2H4(8) + + O2(g) — C2H4Cl2(1) + H2O(1) ArHº = -318.7 kJ mol-1