Question

The amino acid glycine can react to form a dipeptide (glycylgycine) according to the following equation:

2 glycine (s) -----> glycylgycine (s) + H2O (s)

a) Use the data below (taken from standard reference tables) to calculate deltaHdegree (in kJ), deltaSdegree (in J/K), and deltaGdegree (in kJ) corresponding to this reaction at 25 celcius (SHOW WORK)

deltaHdegree (in kJ)

deltaSdegree (in J/K)

deltaGdegree (in kJ)

Chemical Standard enthalpy of formation (kJ/mole) Standard entropy glycine () glycylglycine ) water (I) -537.23 735.72 -285.84 J(mole K)) 103.51 231.38 69.94

b) Will the reaction be more spontaneous (in the forward direction) at body temperature (37 celcius)? Explain.

c) Calculate the equilibrium constant for this reaction at 25 celcius. (SHOW WORK)

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